golang goroutine顺序输出方式_Golang_

 for _, v := range str { go func() { fmt.Println(string(v)) }() }

 for _, c := range str{ ch := make(chan rune) go func(ch <-chan rune) { key := <-ch fmt.Println(string(key)) }(ch) ch <- c } 

 package main import ( "fmt" "sync" ) //控制循环次数 var count = 5 func main() { wg := sync.WaitGroup{} chanA := make(chan struct{}, 1) chanB := make(chan struct{}, 1) chanC := make(chan struct{}, 1) chanA <- struct{}{} wg.Add(3) go printA(&wg, chanA, chanB) go printB(&wg, chanB, chanC) go printC(&wg, chanC, chanA) wg.Wait() } func printA(wg *sync.WaitGroup, chanA, chanB chan struct{}) { defer wg.Done() for i := 0; i < count; i++ { <-chanA fmt.Println("A") chanB <- struct{}{} } } func printB(wg *sync.WaitGroup, chanB, chanC chan struct{}) { defer wg.Done() for i := 0; i < count; i++ { <-chanB fmt.Println("B") chanC <- struct{}{} } } func printC(wg *sync.WaitGroup, chanC, chanA chan struct{}) { defer wg.Done() for i := 0; i < count; i++ { <-chanC fmt.Println("C") chanA <- struct{}{} } } 

 package main import ( "context" "fmt" "time" ) func main() { chanA := make(chan struct{}, 1) chanB := make(chan struct{}, 1) chanC := make(chan struct{}, 1) chanA <- struct{}{} ctx1, cancel1 := context.WithCancel(context.Background()) ctx2, cancel2 := context.WithCancel(context.Background()) ctx3, cancel3 := context.WithCancel(context.Background()) go printA(ctx1, chanA, chanB) go printB(ctx2, chanB, chanC) go printC(ctx3, chanC, chanA) time.Sleep(100 * time.Microsecond) cancel1() cancel2() cancel3() } func printA(ctx context.Context, chanA, chanB chan struct{}) { for { select { case <-ctx.Done(): fmt.Println("cancel by parent") // 不会输出 return case <-chanA: fmt.Println("A") chanB <- struct{}{} } } } func printB(ctx context.Context, chanB, chanC chan struct{}) { for { select { case <-ctx.Done(): fmt.Println("cancel by parent") // 不会输出 return case <-chanB: fmt.Println("B") chanC <- struct{}{} } } } func printC(ctx context.Context, chanC, chanA chan struct{}) { for { select { case <-ctx.Done(): fmt.Println("cancel by parent") // 不会输出 return case <-chanC: fmt.Println("C") chanA <- struct{}{} } } }